Moldovan president to attend UN General Assembly
13:38 | 18.09.2021 Category: Official
Chisinau, 18 September /MOLDPRES/- President Maia Sandu will be in New York, USA, on September 21-22 to participate in the work of the United Nations General Assembly, the presidential press service has reported.
On 22 September Maia Sandu will deliver a speech in the plenary of the UN General Assembly (estimated time - 13.00 / 20.00 Chisinau time).
Also in New York, the head of state will have several bilateral meetings.
Photo: trt.net.tr; Presidency
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